Solution how many squares

The measurement of the space enclosed by the two-dimensional 2D shape of an object is called Area. It is often surrounded by a closed curve shape. Again Take the triangle for example, the space covered by the triangle will be called the area of the triangle.

Solution : The side of the red square on the dotted sheet is 1 cm. Solution : Here are 7 rectangles we can make. Solution : From the above picture we can say that rectangles 1 and 2 has the longest perimeter. Note : You have already read about the perimeter above. If you have not read about it, then you should read it first. The perimeter of all these rectangles will be equal as all rectangles are 3 X 4. Measure stamps. A How many squares of one centimetre side does stamp a cover?

B Which stamp has the biggest area? Solution : Stamp A has the biggest area. Because it has 18 squares of one centimetre side. Solution : This stamp covers 18 squares of side 1 cm. C Which two stamps have the same area? Solution : D and F stamps have the same area.

Solution : The area of each of these stamps is 12 cm 2. Explanation ; From the question B and D , we know that. Area of smallest and biggest stamps are 18 Cm 2 and 4 Cm 2 accordingly.

A Which has the bigger area — one of your footprints or the page of this book? Solution : The area of page of this book is bigger than the area of footprints. B Which has the smaller area — two-five rupee notes together or a hundred rupee note?

Solution : A hundred rupee note. C Look at a 10 rupee note. Solution : No , The area of 10 rupee note is not more than hundred square cm. D Is the area of the blue shape more than the area of the yellow shape? Solution : No , The area of the blue shape is not more than the area of the yellow shape Rather both have the Equal areas.

E Is the perimeter of the yellow shape more than the perimeter of the blue shape? Solution : No , the perimeter of the yellow shape is not more than the perimeter of the blue shape rather the perimeter of blue shape is more than the perimeter of the yellow shape.

Because , With the help of a ruler or thread, we can able to find that the length of the boundary of the blue shape is more than the length of the boundary of the yellow shape. How big is my hand? Ignore less than half filled squares. Note : In this case the answer of all students may be different. My footprints. The same method as the question of Page Solution : Yes , The area of my both footprints are the same.

Solution : The footprint of Chimpanzee and Monkey may have the same area as my footprint. Because we have originated from these.

Guess the area of their footprints. How many squares in me? Solution : The triangle is half the rectangle of area 2 square cm. Solution : If this shape half of the big rectangle , so its area is 4 square cm.

Try triangles. Each of them covers 12 squares of one centimetre side. It covers 4 squares, each of one centimetre side. Is its area more than hundred square cm? We now see that the area of each triangle of the blue shape is more than the area of each triangle of the yellow shape.

We can then say, that the area of the blue shape is more than the area of the yellow shape. Thus, we can say that the perimeter of the blue shape is greater than that of the yellow shape. Trace your hand on the squared sheet on the next page. What is the area of your hand?

We will trace the hand on the paper and find the area of the paper that gets covered by hand with the help of a square of side 1 cm. We will ignore a square if it is less than half-filled but we will count the square as 1, if it is more than half-filled. Figure A covers three squares that are more than half-filled, three squares that are less than half-filled, and three complete squares. Figure B covers four complete squares, eight squares that are half-filled, and four squares that are less than half-filled.

Figure C covers two complete squares, two squares that are more than half-filled, and two squares that are less than half-filled. Figure D covers five complete squares and two squares that are half-filled. Figure E covers 18 complete squares and six squares that are half-filled.

Figure F covers four squares that are more than half-filled, four squares that are less than half-filled, and four complete squares. The blue triangle is half of the big rectangle. Area of the big rectangle is 20 square cm. Now you find the area of the two rectangles Sadiq is talking about. What is the area of the red triangle? There are two rectangles. The orange rectangle contains 12 complete squares and the green rectangle contains 8 complete squares. Suruchi drew two sides of a shape.

She asked Asif to complete the shape with two more sides, so that its area is 10 square cm. He completed the shape like this. In the yellow portion, we have three complete squares, three squares that are more than half-filled, and two squares that are less than half-filled.

Practice time This is one of the sides of a shape. Complete the shape so that its area is 4 square cm. Practice time Two sides of a shape are drawn here. It only takes a minute to sign up. Connect and share knowledge within a single location that is structured and easy to search. Well, sort of, you can look at each "atom" piece and count how many squares that is the upper right hand corner of.

This i a simplification of simply figuring out the squares in a complete grid and subtracting the one that rectangles make impossible. A 4x4 grid will have: 16 1x1 squares; 9 2x2 squares as there are 3 squares in each of the top 3 rows that can be an upper right hand corner of a 3x3 square , 4 3x3 squares, and 1 4x4 square.

The right side triangle eliminates 2 1x1 squares 1 2x2 that was already eliminated and a 3x3. So only 21 possible. Where is the number of hashes. A hash being division of a square by a set of orthogonal equally spaced including overlapping ; as is the initial case parallel lines such that the corner square is exactly one fourth the area of the centre square. Well the answer is How I do these problems is first i count the 1x1 squares. There is 8 of them.

Then I count the 2x2 squares. There is 5 of them. Then 3x3 squares. There is four of them. And then the 4x4 square. Total In each square size I go from left to right top to bottom. In each open space, I counted the number of squares that shared the upper left corner. Can't be an even number as only one outside square.